disk_total_space

(PHP 4 >= 4.1.0, PHP 5)

disk_total_space — Gibt die Gesamtgröße eines Dateisystemes oder einer Partition zurück

Beschreibung

float disk_total_space ( string $directory )

Wird eine Zeichenkette, die einen Verzeichnispfad enthält übergeben, wird diese Funktion, die Gesamtanzahl Bytes auf dem entsprechenden Dateisystem oder der Platten-Partition zurückgeben.

Parameter-Liste

directory: Ein Verzeichnis des Dateisystemes oder der Platten-Partition.

Rückgabewerte

Gibt die Gesamtanzahl Bytes als Gleitkommazahl (float) zurück. Im Fehlerfall wird FALSE zurückgegeben..

Beispiele

Beispiel #1 disk_total_space() Beispiel


<?php
// $ds enthält die Gesamtanzahl verfügbarer Bytes auf "/"
$ds = disk_total_space("/");

// On Windows:
$ds = disk_total_space("C:");
$ds = disk_total_space("D:");
?>

Anmerkungen

Hinweis: Diese Funktion kann nicht mit entfernten Dateien arbeiten, da der Zugriff auf die Datei, die bearbeitet werden soll, über das Dateisystem des Servers möglich sein muss.

Siehe auch

disk_free_space() - Gibt verfügbaren Platz auf Dateisystem oder Partition zurück

add a note User Contributed Notes
disk_total_space

tularis at php dot net
25-Jun-2007 12:13


For a non-looping way to add symbols to a number of bytes:

<?php

function getSymbolByQuantity($bytes) {

    $symbols = array('B', 'KiB', 'MiB', 'GiB', 'TiB', 'PiB', 'EiB', 'ZiB', 'YiB');

    $exp = floor(log($bytes)/log(1024));



    return sprintf('%.2f '.$symbol[$exp], ($bytes/pow(1024, floor($exp))));

}

stierguy1 at msn dot com
25-Jun-2007 04:03


function roundsize($size){

    $i=0;

    $iec = array("B", "Kb", "Mb", "Gb", "Tb");

    while (($size/1024)>1) {

        $size=$size/1024;

        $i++;}

    return(round($size,1)." ".$iec[$i]);}

nikolayku at tut dot by
17-Apr-2007 10:16


Very simple function that convert bytes to kilobytes, megabytes ...



function ConvertBytes($number)

{

    $len = strlen($number);

    if($len < 4)

    {

        return sprintf("%d b", $number);

    }

    if($len >= 4 && $len <=6)

    {

        return sprintf("%0.2f Kb", $number/1024);

    }

    if($len >= 7 && $len <=9)

    {

        return sprintf("%0.2f Mb", $number/1024/1024);

    }

    

    return sprintf("%0.2f Gb", $number/1024/1024/1024);

                            

}

Mat
05-Apr-2007 12:46


JulieC:



I think you may have misunderstood - given a directory, this function tells you how big the disk paritition is that the directory exists on.



So disk_total_space("C:\Windows\") will tell you how big drive C is.



It is not suggesting that a directory is a disk partition.

JulieC
31-Jan-2007 04:11


"filesystem or disk partition" does not equal "directory" for Windows.  Thanks.

martijn at mo dot com
13-Jan-2007 11:41


This works for me (on a UNIX server):



<?php

function du( $dir ) 

{ 

    $res = `du -sk $dir`;             // Unix command

    preg_match( '/\d+/', $res, $KB ); // Parse result

    $MB = round( $KB[0] / 1024, 1 );  // From kilobytes to megabytes

    return $MB;

} 



$dirSize = du('/path/to/dir/');

?>

shalless at rubix dot net dot au
16-Jul-2003 04:36


My first contribution. Trouble is the sum of the byte sizes of the files in your directories is not equal to the amount of disk space consumed, as andudi points out. A 1-byte file occupies 4096 bytes of disk space if the block size is 4096. Couldn't understand why andudi did $s["blksize"]*$s["blocks"]/8. Could only be because $s["blocks"] counts the number of 512-byte disk blocks not the number of $s["blksize"] blocks, so it may as well just be $s["blocks"]*512. Furthermore none of the dirspace suggestions allow for the fact that directories are also files and that they also consume disk space. The following code dskspace addresses all these issues and can also be used to return the disk space consumed by a single non-directory file. It will return much larger numbers than you would have been seeing with any of the other suggestions but I think they are much more realistic:





<?php


function dskspace($dir)


{ 


   $s = stat($dir);


   $space = $s["blocks"]*512;


   if (is_dir($dir))


   { 


     $dh = opendir($dir); 


     while (($file = readdir($dh)) !== false)


       if ($file != "." and $file != "..") 


         $space += dskspace($dir."/".$file); 


     closedir($dh);


   } 


   return $space; 


}


?>

andudi at gmx dot ch
12-Jun-2002 12:15


To find the total size of a file/directory you have to differ two situations:

(on Linux/Unix based systems only!?)



you are interested:

1) in the total size of the files in the dir/subdirs

2) what place on the disk your dir/subdirs/files uses



- 1) and 2) normaly differs, depending on the size of the inodes

- mostly 2) is greater than 1) (in the order of any kB)

- filesize($file) gives 1)

- "du -ab $file" gives 2)



so you have to choose your situation!



on my server I have no rights to use "exec du" in the case of 2), so I use:

  $s = stat($file);

  $size = $s[11]*$s[12]/8);

whitch is counting the inodes [12] times the size of them in Bits [11]



hopes this helps to count the used disk place in a right way... :-)



                     Andreas Dick

kit at 4me dot ru
28-Jun-2001 11:57


I just did the simple thing -





<?php


function du($dir)


{


    $du = popen("/usr/bin/du -sk $dir", "r");


    $res = fgets($du, 256);


    pclose($du);


    $res = explode(" ", $res);


    


    return $res[0];


}


?>

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diskfreespace

disk_free_space

Last updated: Fri, 18 May 2012